%I #68 Sep 08 2022 08:45:40
%S 10,16,26,22,36,50,28,46,64,82,34,56,78,100,122,40,66,92,118,144,170,
%T 46,76,106,136,166,196,226,52,86,120,154,188,222,256,290,58,96,134,
%U 172,210,248,286,324,362,64,106,148,190,232,274,316,358,400,442,70,116,162
%N Triangle T(n, k) = 4*n*k + 2*n + 2*k + 2, read by rows.
%C First column: A016957, second column: A017341, third column: 2*A017029, fourth column: A082286. - _Vincenzo Librandi_, Nov 21 2012
%C Conjecture: Let p = prime number. If 2^p belongs to the sequence, then 2^p-1 is not a Mersenne prime. - _Vincenzo Librandi_, Dec 12 2012
%C Conjecture is true because if T(n, k) = 2^p with p prime, then 2^p-1 = 4*n*k + 2*n + 2*k + 1 = (2*n+1)*(2*k+1) hence 2^p-1 is not prime. - _Michel Marcus_, May 31 2015
%C It appears that T(m,p) = 2^p for Lucasian primes (A002515) greater than 3. For instance: T(44, 11) = 2^11, T(89240, 23) = 2^23. - _Michel Marcus_, May 28 2015
%C For n > 1, ascending numbers along the diagonal are also terms of the even principal diagonal of a 2n X 2n spiral (A137928). - _Avi Friedlich_, May 21 2015
%H Vincenzo Librandi, <a href="/A155151/b155151.txt">Rows n = 1..100, flattened</a>
%F T(n, k) = 2*A144650(n, k).
%F Sum_{k=1..n} T(n,k) = n*(2*n^2 + 5*n + 3) = n*A014105(n+2) =
%e Triangle begins
%e 10;
%e 16, 26;
%e 22, 36, 50;
%e 28, 46, 64, 82;
%e 34, 56, 78, 100, 122;
%e 40, 66, 92, 118, 144, 170;
%e 46, 76, 106, 136, 166, 196, 226;
%e 52, 86, 120, 154, 188, 222, 256, 290;
%e 58, 96, 134, 172, 210, 248, 286, 324, 362;
%e 64, 106, 148, 190, 232, 274, 316, 358, 400, 442;
%p seq(seq( 2*(2*n*k+n+k+1), k=1..n), n=1..15) # _G. C. Greubel_, Mar 21 2021
%t T[n_,k_]:=4*n*k + 2*n + 2*k + 2; Table[T[n, k], {n, 11}, {k, n}]//Flatten (* _Vincenzo Librandi_, Nov 21 2012 *)
%o (Magma) [4*n*k + 2*n + 2*k + 2: k in [1..n], n in [1..11]]; // _Vincenzo Librandi_, Nov 21 2012
%o (Sage) flatten([[2*(2*n*k+n+k+1) for k in (1..n)] for n in (1..15)]) # _G. C. Greubel_, Mar 21 2021
%Y Cf. A000043, A000668, A016957, A017029, A017341, A054723, A082286, A144650.
%K nonn,tabl,easy
%O 1,1
%A _Vincenzo Librandi_, Jan 21 2009
%E Edited by _Robert Hochberg_, Jun 21 2010