%I #11 Apr 16 2022 15:00:38
%S 1,2,1,2,1,3,1,10,1,1835,1
%N a(n) = floor(zeta(zeta(...zeta(2)...))), where zeta appears n times; zeta is the Riemann zeta function.
%C a(n)=1 for odd n; a(12) (see the b-file) is too large to display here.
%H Vladimir Reshetnikov, <a href="/A154819/b154819.txt">Table of n, a(n) for n = 1..12</a>
%e a(1) = floor(zeta(2)); a(2) = floor(zeta(zeta(2)));
%t Block[{$MaxExtraPrecision = Infinity}, Table[Floor[Nest[Zeta, 2, n]], {n, 1, 12}]]
%K nonn
%O 1,2
%A _Vladimir Reshetnikov_, Jan 15 2009