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%I #7 May 10 2019 16:50:34
%S 3,23,27,261,348,2720,72944,347065,244543
%N Greatest number m such that the fractional part of e^A153704(n) >= 1-(1/m).
%F a(n) = floor(1/(1-fract(e^A153704(n)))), where fract(x) = x-floor(x).
%e a(2) = 23, since 1-(1/24) = 0.9583... > fract(e^A153704(2)) = fract(e^8) = 0.95798... >= 0.95652... >= 1-(1/23).
%t A153704 = {1, 8, 19, 178, 209, 1907, 32653, 119136, 220010};
%t Table[fp = FractionalPart[E^A153704[[n]]]; m = Floor[1/fp];
%t While[fp >= 1 - (1/m), m++]; m - 1, {n, 1, Length[A153704]}] (* _Robert Price_, May 10 2019 *)
%Y Cf. A153664, A153672, A153680, A153688, A153696, A153704, A154130, A153716, A153724.
%Y Cf. A000149.
%K nonn,more
%O 1,1
%A _Hieronymus Fischer_, Jan 06 2009
%E a(8)-a(9) from _Robert Price_, May 10 2019
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