A153669 Minimal exponents m such that the fractional part of (101/100)^m obtains a minimum (when starting with m=1).

1, 70, 209, 378, 1653, 2697, 4806, 13744, 66919, 67873, 75666, 81125, 173389, 529938, 1572706, 4751419, 7159431, 7840546, 15896994, 71074288, 119325567

Offset

1,2

Comments

Recursive definition: a(1)=1, a(n) = least number m>a(n-1) such that the fractional part of (101/100)^m is less than the fractional part of (101/100)^k for all k, 1<=k<m.

The next term is greater than 2*10^8.

Links

Table of n, a(n) for n=1..21.

Formula

Recursion: a(1):=1, a(k):=min{ m>1 | fract((101/100)^m) < fract((101/100)^a(k-1))}, where fract(x) = x-floor(x).

Example

a(2)=70, since fract((101/100)^70)=0.00676..., but fract((101/100)^k)>=0.01 for 1<=k<=69; thus fract((101/100)^70)<fract((101/100)^k) for 1<=k<70.

Mathematica

p = 1; Select[Range[1, 5000],
If[FractionalPart[(101/100)^#] < p, p = FractionalPart[(101/100)^#];
True] &] (* Robert Price, Mar 21 2019 *)

Crossrefs

Cf. A081464, A154130, A153673, A153677, A153685, A153693, A153701, A137994, A153717.

Sequence in context: A154361 A165762 A165764 * A235310 A235303 A234564

Adjacent sequences: A153666 A153667 A153668 * A153670 A153671 A153672

Keyword

nonn,more

Author

Hieronymus Fischer, Jan 06 2009

Extensions

a(15)-a(21) from Robert Gerbicz, Nov 22 2010

Status

approved