A153055 - OEIS

%I #3 Mar 31 2012 10:29:57

%S 11,13,27,29,45,53,54,59,61,79,83,101,103,106,109,115,121,125,155,158,

%T 163,166,173,181,187,199,202,206,211,212,213,218,237,251,310,326,329,

%U 345,346,362,369,377,393,398,407,409,412,422,436,441,459,563,575,581

%N Numbers n such that the binary expansion of n is a substring of the binary expansion of 1/n.

%e a(2) = 13 because bin(13)=1101 and bin(1/13)=.000100111011(repeats infinitely) and 1101 appears in the binary expansion of the reciprocal.

%K base,easy,nonn

%O 1,1

%A _Gil Broussard_, Dec 17 2008