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17^(2^n) + 2.
0

%I #7 Oct 01 2013 21:35:28

%S 19,291,83523,6975757443,48661191875666868483,

%T 2367911594760467245844106297320951247363,

%U 5607005320601059253161325667991103602003892399764752527847859167616581809464323

%N 17^(2^n) + 2.

%C Except for the first term, these numbers are divisible by 3.

%t Table[17^2^n + 2, {n, 0, 6}] (* _Arkadiusz Wesolowski_, Jun 03 2013 *)

%o (PARI) g(a,n) = if(a%2,b=2,b=1);for(x=0,n,y=a^(2^x)+b;print1

%o (y","))

%K easy,nonn

%O 0,1

%A _Cino Hilliard_, Dec 08 2008

%E Name corrected by _Arkadiusz Wesolowski_, Jun 03 2013