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a(n) = -5*a(n-1) + 7*a(n-2) for n > 1 with a(0) = 1 and a(1) = -7.
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%I #26 Apr 09 2024 08:09:14

%S 1,-7,42,-259,1589,-9758,59913,-367871,2258746,-13868827,85155357,

%T -522858574,3210380369,-19711911863,121032221898,-743144492531,

%U 4562948015941,-28016751527422,172024393748697,-1056239229435439

%N a(n) = -5*a(n-1) + 7*a(n-2) for n > 1 with a(0) = 1 and a(1) = -7.

%H Harvey P. Dale, <a href="/A152239/b152239.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (-5,7).

%F G.f.: (1 - 2*x)/(1 + 5*x - 7*x^2).

%F a(n) = Sum_{k=0..n} A147703(n,k)*(-8)^k.

%t LinearRecurrence[{-5,7},{1,-7},20] (* _Harvey P. Dale_, Apr 14 2022 *)

%o (PARI) Vec((1-2*x)/(1+5*x-7*x^2)+O(x^99)) \\ _Charles R Greathouse IV_, Jan 17 2012

%Y Cf. A147703.

%K sign,easy,less

%O 0,2

%A _Philippe Deléham_, Nov 30 2008

%E Several terms corrected by _Johannes W. Meijer_, Aug 17 2010