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a(n) = the smallest positive integer m such that A152221(m) = n.
1

%I #6 Apr 09 2014 10:16:43

%S 1,2,6,12,20,13,14,56,72,41,43,44,108,29,30,240,272,145,147,83,84,86,

%T 183,184,408,410,218,220,476,61,62,992,1056,545,547,291,293,613,615,

%U 1256,1320,169,171,172,364,366,751,752,1584,1586,818,820,1716,437,439

%N a(n) = the smallest positive integer m such that A152221(m) = n.

%e 12 represented in binary is 1100. A152221(12) = 3 because the binary representation of 3 (which is 11) occurs in 1100 (like so: (11)00), the binary representation of 4 (which is 100) occurs in 1100 (like so: 1(100)) and no larger pair of consecutive integers occurs within 1100. Since no positive integer m, m < 12, is such that A152221(m) = 3, then a(3) = 12.

%Y A152221

%K base,nonn

%O 0,2

%A _Leroy Quet_, Nov 29 2008

%E Extended by _Ray Chandler_, Dec 05 2008