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Consider pairs m,n such that UnitaryPhi(m) = UnitaryPhi(n) = (1/8)*(5*m^(1/2)-3*n^(1/2))^2, m<n. Sequence gives m numbers.
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%I #2 Apr 19 2016 01:10:16

%S 2152640,11948993133919100295708672000

%N Consider pairs m,n such that UnitaryPhi(m) = UnitaryPhi(n) = (1/8)*(5*m^(1/2)-3*n^(1/2))^2, m<n. Sequence gives m numbers.

%C If m=n then we get A030163.

%e Factorizations:

%e 2^6*5*7*31^2

%e 2^22*5^3*7^2*11^3*19*23*31^2*683*3^4*13^2

%K nonn,bref

%O 1,1

%A _Yasutoshi Kohmoto_, Jan 11 2009