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a(0) = 0; thereafter, a(n+1) = (a(n) + 2)^2 - n.
1

%I #4 Mar 31 2012 12:38:16

%S 0,3,23,622,389372,151612111871,22986232466591067568123,

%T 528366883008165274204418444362589201516015618,

%U 279171563059764209960524428253973697688487588192684862752843397296212343984911360083984392

%N a(0) = 0; thereafter, a(n+1) = (a(n) + 2)^2 - n.

%t lst={}; a=0; Do[AppendTo[lst,a=a^2-n]; a=a+2,{n,0,9}]; lst

%K nonn

%O 0,2

%A _Vladimir Joseph Stephan Orlovsky_, Sep 06 2008

%E Edited by _N. J. A. Sloane_, Sep 14 2008, Jan 02 2009