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%I #12 Feb 05 2013 09:07:31
%S 1,1,3,1,3,5,1,1,5,7,3,1,5,7,3,9,1,5,7,1,9,11,3,7,1,11,5,13,3,7,1,9,5,
%T 11,13,1,15,7,9,5,3,11,1,13,15,17,5,3,1,11,7,13,9,17,19,1,11,7,13,5,
%U 15,9,3
%N Concerning hypotenuses of triangles such that the sum of the two legs is a perfect square.
%C The sequence of a's considered in A145906.
%H M. de Frenicle, <a href="http://gallica.bnf.fr/ark:/12148/bpt6k5493994j/">Methode pour trouver la solutions des problemes par les exclusions</a>, in: Divers ouvrages de mathematiques et de physique par messieurs de l'academie royale des sciences, (1693) pp 1-44, Table on page 31.
%e (a,b,c,d,e,f,g,h) = (1,2,1,3,1,5,4,9) with N=7 or (1,3,2,5,7,13,6,19) with N=17 or (3,4,1,5,7,17,10,27) with N=23 or (1,4,3,7,17,25,8,33) with N=31.
%K nonn,uned
%O 1,3
%A _Paul Curtz_, Aug 30 2008
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