%I #7 Apr 09 2014 10:15:20
%S 3,5,3,5,4,5,3,5,9,3,9,5,3,5,8,9,6,9,5,4,7,5,8,10,5,3,5,4,5,15,5,9,3,
%T 14,3,9,10,5,10,8,6,11,4,5,3,17,13,5,4,5,7,6,11,9,7,8,3,8,5,3,13,21,5,
%U 4,5,20,9,11,4,5,7,15,10,9,5,9,15,5,9,11,7,11,4,7,5,8,13,5,3,5,14,13,5,9,5
%N a(n) = the largest integer such that each positive integer <= a(n) divides at least one integer k, where the n-th prime <= k <= the (n+1)th prime.
%C a(n) = A142973(n) - 1.
%e The 15th prime is 47 and the 16th prime is 53. So we will consider the integers 47,48,49,50,51,52,53. Now, 1 divides each of these 6 integers. 2 divides 48, 50 and 52. 3 divides 48 and 51. 4 divides 48 and 52. 5 divides 50. 6 divides 48. 7 divides 49. 8 divides 48. But 9 does not divide any integer that is between 47 and 53. So a(15)=8, since 1, 2, 3, 4, 5, 6, 7 and 8 each divide at least one integer between 47 and 53.
%Y Cf. A142973.
%K nonn
%O 1,1
%A _Leroy Quet_, Jul 14 2008
%E Extended by _Ray Chandler_, Jun 21 2009