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%I #5 Mar 31 2012 13:23:39
%S 0,4,3,12,16,19,20,7,8,15,11,23,77,73,74,85,86,78,82,90,94,89,93,81,
%T 63,60,64,71,67,51,48,56,59,68,55,52,108,112,111,104,107,119,115,99,
%U 96,103,100,116,46,45,42,29,25,34,33,41,37,26,38,30
%N Bisect sequence A057113.
%C Since A057113 is generated based on A057112(n) and successive transpositions, we can be assured that A141826(n) will always map (using A055089)to permutation with an even number of transpositions (applicable, e.g. to the Icosahedron and truncated icosahedron studied in the Geometry Center at http://www.scienceu.com/geometry/facts/solids/handson.html ).
%e A057113(n)is 0 1 4 5 3 2 12 13 16 22 19 18 20 10 7 6 8 14 15 9 11 21 23 17 77... so the sequence begins 0 4 3 12 16 19 20 7 8 15 11 23 77 ...
%Y Cf. A055089, A057112, A057113.
%K easy,nonn
%O 0,2
%A _Alford Arnold_, Aug 07 2008
%E More terms from _Alford Arnold_, Aug 18 2008