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a(n) = n mod ((sum of digits of n)+1).
2

%I #13 Apr 25 2019 15:39:57

%S 0,1,2,3,4,5,6,7,8,9,0,2,0,3,2,1,0,8,8,8,2,1,2,5,3,1,8,7,6,5,2,1,2,5,

%T 2,8,6,4,2,0,0,5,0,3,8,5,2,11,9,7,2,2,4,8,4,0,8,5,2,14,4,5,8,3,9,5,1,

%U 11,8,5,6,8,2,7,2,10,6,2,14,11,8,1,5,11

%N a(n) = n mod ((sum of digits of n)+1).

%H Robert Israel, <a href="/A141022/b141022.txt">Table of n, a(n) for n = 0..10000</a>

%p P:=proc(n) local i, k, w; for i from 1 by 1 to n do w:=0; k:=i; while k>0 do w:=w+k-trunc(k/10)*10; k:=trunc(k/10); od; print(i mod (w+1)); od; end: P(1000);

%o (PARI) a(n) = n % (1+sumdigits(n)); \\ _Michel Marcus_, Jun 04 2014

%Y Cf. A007953.

%K nonn,base,less

%O 0,3

%A Olivier Bouaziz (olivier.bouaziz(AT)arcelormittal.com), Jul 29 2008

%E More terms from _Michel Marcus_, Jun 04 2014