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%I #6 Mar 30 2012 18:51:58
%S 1,3,5,6,10,11,12,20,21,22,24,40,42,43,44,48,80,84,85,86,88,96,160,
%T 168,170,171,172,176,192,320,336,340,341,342,344,352,384,640
%N Based on Jacobsthal numbers. Increasing order of different positive terms of A140950.
%C Two possibilities of triangle on line. 1) From 1: 1; 3, 5; 6, 10, 11; 12, 20, 21, 22; 24, 40, 42, 43, 44; . 2) After 1: 3; 5, 6; 10, 11, 12; 20, 21, 22, 24; .
%F Also A140642 (1, 2, 3, 4, 5, 6, 8, 10, 11, 12, 16, 20) without A000079(n+1). Note position of A001045(n+2) terms: 0, 1, 2, 5, 8, 13 =A000982. See A140503 square .
%K nonn,uned
%O 0,2
%A _Paul Curtz_, Jul 25 2008