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 A140449 a(n) = the multiple of A142972(n) such that the n-th prime <= a(n) <= the (n+1)th prime. 0
 3, 5, 6, 10, 12, 15, 18, 20, 27, 30, 36, 40, 42, 45, 48, 54, 60, 63, 70, 72, 77, 80, 88, 90, 100, 102, 105, 108, 110, 120, 130, 135, 138, 140, 150, 153, 160, 165, 170, 176, 180, 187, 192, 195, 198, 204, 221, 225, 228, 230, 238, 240, 242, 252, 259, 264, 270, 272 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS There is always only one multiple of A142972(n) that is between the n-th prime and the (n+1)th prime. LINKS EXAMPLE The 15th prime is 47 and the 16th prime is 53. So we will examine the integers 47,48,49,50,51,52,53. Now, 1 divides each of these integers. 2 divides 48,50,52. 3 divides 48 and 51. 4 divides 48 and 52. 5 divides 50. 6 divides 48. 7 divides 49. 8 divides 48. But 9 doesn't divide any integer in the span of consecutive integers 47 to 53. So 8 is the largest integer m such that 1,2,3,4,...m each divide at least one integer in the span 47 to 53. 48 is the multiple of 8 among the integers in the span. So a(15) = 48. CROSSREFS Cf. A142972. Sequence in context: A028927 A099190 A122772 * A207063 A230851 A334101 Adjacent sequences:  A140446 A140447 A140448 * A140450 A140451 A140452 KEYWORD nonn AUTHOR Leroy Quet, Jul 21 2008 EXTENSIONS Extended by Ray Chandler, Jun 21 2009 STATUS approved

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Last modified May 18 11:30 EDT 2021. Contains 343995 sequences. (Running on oeis4.)