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%I #2 Mar 30 2012 17:27:55
%S 2,6,7,8,11,12,13,14,17,18,19,20,21,27,28,29,30,31,32,33,34,35,38,39,
%T 40,41,42,43,44,45,46,47,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,
%U 71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,94,95,96,97,98,99,100,101
%N Complement of A136120.
%C k-th run of consecutive numbers has length A136120(k).
%e A136120 starts 1, 3, 4, 5, 9, 10, 15, ..., so sequence starts 2, 6, 7, 8, 11, 12, ... .
%Y Cf. A136120, A139419, A139420.
%K easy,nonn
%O 1,1
%A _Klaus Brockhaus_, Apr 22 2008
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