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a(n)=8a(n-4).
1

%I #9 Jun 03 2026 16:16:41

%S 1,3,4,4,8,24,32,32,64,192,256,256,512,1536,2048,2048,4096,12288,

%T 16384,16384,32768

%N a(n)=8a(n-4).

%H Harvey P. Dale, <a href="/A137529/b137529.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,8).

%t LinearRecurrence[{0,0,0,8},{1,3,4,4},30] (* _Harvey P. Dale_, Apr 13 2025 *)

%o (PARI) a(n)=([0,1,0,0; 0,0,1,0; 0,0,0,1; 8,0,0,0]^n*[1;3;4;4])[1,1] \\ _Charles R Greathouse IV_, Jun 03 2026

%K nonn,easy

%O 0,2

%A _Paul Curtz_, Apr 25 2008