login
A136496
Solution of the complementary equation b(n)=a(a(n))+n; this is sequence b; sequence a is A136495.
2
2, 6, 8, 11, 15, 19, 21, 25, 27, 30, 34, 36, 39, 43, 47, 49, 52, 56, 60, 62, 66, 68, 71, 75, 79, 81, 85, 87, 90, 94, 96, 99, 103, 107, 109, 113, 115, 118, 122, 124, 127, 131, 135, 137, 140, 144, 148, 150, 154, 156, 159, 163, 165, 168, 172, 176, 178, 181, 185, 189
OFFSET
1,1
COMMENTS
b = 1 + (column 1 of Z) = 1 + A020942. The pair (a,b) also satisfy the following complementary equations: b(n)=a(a(a(n)))+1; a(b(n))=a(n)+b(n); b(a(n))=a(n)+b(n)-1; (and others).
REFERENCES
Clark Kimberling and Peter J. C. Moses, Complementary equations and Zeckendorf arrays, in Applications of Fibonacci Numbers, vol.10, Proceedings of the Thirteenth International Conference on Fibonacci Numbers and Their Applications, William Webb, editor, Congressus Numerantium, Winnipeg, Manitoba 201 (2010) 161-178.
FORMULA
Let Z = (3rd order Zeckendorf array) = A136189. Then a = ordered union of columns 1,3,4,6,7,9,10,12,13,... of Z, b = ordered union of columns 2,5,8,11,14,... of Z.
EXAMPLE
b(1) = a(a(1))+1 = a(1)+1 = 1+1 = 2;
b(2) = a(a(2))+2 = a(3)+2 = 4+2 = 6;
b(3) = a(a(3))+3 = a(4)+3 = 5+3 = 8;
b(4) = a(a(4))+4 = a(5)+4 = 7+4 = 11.
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Jan 01 2008
STATUS
approved