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%I #12 Aug 02 2018 17:06:50
%S 1,1,2,3,3,3,5,5,5,5,3,3,3,3,3,6,6,6,6,6,6,17,17,17,17,17,17,17,2,2,2,
%T 2,2,2,2,2,11,11,11,11,11,11,11,11,11,10,10,10,10,10,10,10,10,10,10,
%U 25,25,25,25,25,25,25,25,25,25,25,11,12,12,12,12,12
%N a(1)=1. Let m be the number of terms in the longest run of consecutive equal terms from among the first n terms of the sequence. a(n+1) = the number of terms, from among the first n terms of the sequence, that divide m.
%H Rémy Sigrist, <a href="/A136348/b136348.txt">Table of n, a(n) for n = 1..10000</a>
%H Rémy Sigrist, <a href="/A136348/a136348.gp.txt">PARI program for A136348</a>
%e Among the first 20 terms of the sequence the run of five 3's (from a(11) to a(15)) is the longest run of consecutive equal terms. (So m = 5.) Among the first 20 terms of the sequence, there are six which divide 5. (a(1),a(2),a(7),a(8),a(9),a(10)) So a(21) = 6.
%o (PARI) See Links section.
%Y Cf. A136347.
%K nonn,look
%O 1,3
%A _Leroy Quet_, Dec 25 2007
%E More terms from _Rémy Sigrist_, Aug 02 2018
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