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%I #11 Aug 02 2018 17:07:49
%S 1,1,2,2,2,5,6,6,6,6,3,4,4,4,4,4,15,15,15,15,15,15,3,3,3,3,3,3,3,29,
%T 30,31,32,33,34,35,35,35,35,35,35,35,35,28,28,28,28,28,28,28,28,28,32,
%U 33,33,33,33,33,33,33,33,33,33,23,24,24,24,24,24,24,24
%N a(1)=1. Let m be the number of terms in the longest run of consecutive equal terms from among the first n terms of the sequence. a(n+1) = the number of terms, from among the first n terms of the sequence, that are coprime to m.
%H Rémy Sigrist, <a href="/A136347/b136347.txt">Table of n, a(n) for n = 1..10000</a>
%H Rémy Sigrist, <a href="/A136347/a136347.gp.txt">PARI program for A136347</a>
%e Among the first 30 terms of the sequence the run of seven 3's (from a(23) to a(29)) is the longest run of consecutive equal terms. (So m = 7.) Among the first 30 terms of the sequence, all 30 terms are coprime to 7. So a(31) = 30.
%o (PARI) See Links section.
%Y Cf. A136348.
%K nonn,look
%O 1,3
%A _Leroy Quet_, Dec 25 2007
%E More terms from _Rémy Sigrist_, Aug 02 2018
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