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Triangle read by rows, T(0,0) = 1; n-th row = (n+1) terms of n, n+1, n+2, ...
3

%I #23 Mar 26 2022 11:10:56

%S 1,1,2,2,3,4,3,4,5,6,4,5,6,7,8,5,6,7,8,9,10,6,7,8,9,10,11,12,7,8,9,10,

%T 11,12,13,14,8,9,10,11,12,13,14,15,16,9,10,11,12,13,14,15,16,17,18

%N Triangle read by rows, T(0,0) = 1; n-th row = (n+1) terms of n, n+1, n+2, ...

%C Apart from the irregular choice of T(0,0) the same as A051162. - _R. J. Mathar_, Mar 28 2012

%H G. C. Greubel, <a href="/A134478/b134478.txt">Table of n, a(n) for the first 100 rows, flattened</a>

%e First few rows of the triangle:

%e 1;

%e 1, 2;

%e 2, 3, 4;

%e 3, 4, 5, 6;

%e 4, 5, 6, 7, 8;

%e 5, 6, 7, 8, 9, 10;

%e 6, 7, 8, 9, 10, 11, 12;

%e 7, 8, 9, 10, 11, 12, 13, 14;

%e ...

%t Join[{1},Flatten[Table[Range[n,2n],{n,10}]]] (* _Harvey P. Dale_, Nov 21 2014 *)

%o (PARI) concat([1], for(n=1,10, for(k=0,n, print1(n+k, ", ")))) \\ _G. C. Greubel_, Sep 24 2017

%Y Cf. A051162, A134479 (row sums), A126804 (row products).

%K nonn,less,tabl

%O 0,3

%A _Gary W. Adamson_, Oct 27 2007