%I #11 Mar 25 2022 03:02:47
%S 1,3,10,32,101,315,975,3001,9199,28109,85680,260650,791663,2401313
%N Binomial transform of A045621.
%C Given A045621 starting (1, 2, 5, 10, 22, 44, 93, ...).
%C (Note that this uses an incorrect offset of -1 with A045621. - _R. J. Mathar_, Apr 04 2012)
%F A007318 * A045621, A045621 starting with "1".
%e a(4) = 32 = (1, 3, 3, 1) dot (1, 2, 5, 10) = (1 + 6 + 15 + 10).
%Y Cf. A045621.
%K nonn,more
%O 1,2
%A _Gary W. Adamson_, Oct 22 2007