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a(n) = ((2n)!)^3.
4

%I #9 Oct 03 2017 05:43:01

%S 1,8,13824,373248000,65548320768000,47784725839872000000,

%T 109903340320478724096000000,662559760549147780765974528000000,

%U 9159226129831418921308831875072000000000

%N a(n) = ((2n)!)^3.

%H Christian Elsholtz, <a href="https://arxiv.org/abs/1604.06903">Golomb’s Conjecture on Prime Gaps</a>, arXiv:1604.06903 [math.NT], 2016.

%H Christian Elsholtz, <a href="http://www.jstor.org/stable/10.4169/amer.math.monthly.124.4.365">Golomb’s Conjecture on Prime Gaps</a>, The American Mathematical Monthly 124.4 (2017): 365-368.

%t Table[((2n)!)^(3), {n, 0, 10}]

%t ((2*Range[0, 10])!)^3 (* _Harvey P. Dale_, Jul 25 2016 *)

%Y Cf. A000142, A001044, A000442, A036740, A010050, A134366, A134367, A134368, A134369, A134371, A134373, A134374, A134375.

%K nonn

%O 0,2

%A _Artur Jasinski_, Oct 22 2007

%E Definition corrected by _Harvey P. Dale_, Jul 25 2016