%I #2 Mar 31 2012 13:21:04
%S 0,2,2,4,2,5,2,6,4,6,2,8,2,6,5,8,2,9,2,8,5,7,2,10,4,7,6,8,2,12,2,10,6,
%T 8,5,12,2,8,6,11,2,12,2,9,8,8,2,13,4,10,6,9,2,12,5,11,6,8,2,14,2,8,8,
%U 12,5,13,2,10,6,13,2,14,2,9,8,10,5,13,2,13,8,10,2,17,5,9,7,11,2,16,5,10,7,9
%N Number of prime factors (counted with multiplicity) of the period numbers defined by A133900.
%F a(n)=A001222(A133900(n)).
%e a(6)=5, since A133900(6)=72=2*2*2*3*3.
%e a(12)=8, since A133900(12)=864=2*2*2*2*2*3*3*3.
%Y Cf. A000040, A001222, A100118, A046363, A133620, A133621, A133623, A133630, A133635.
%Y Cf. A133872, A133880, A133890, A133900, A133910, A134331.
%K nonn
%O 1,2
%A _Hieronymus Fischer_, Oct 20 2007