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%I #9 May 27 2021 09:22:57
%S 1,1,7,11,8,8,0,0,6,2,2,2,4,4,4,0,3,3,9,9,0,0,0,0,0,0,0,4,4,4,8,8,5,9,
%T 3,3,8,8,8,4,10,10,6,6,0,0,0,0,3,3,9,9,0,0,4,4,4,8,8,8,0,0,0,8,5,5,7,
%U 7,4,0,0,0,6,6,6,6,0,0,0,0,3,7,1,1,8,8,8,0,0,0,8,8,8,4,4,4,9,9,3,3,0,0,0,0
%N a(n) = binomial(n+p,n) mod p, where p=12.
%C Periodic with length 6*12^2 = 864 = A133900(12).
%F a(n) = binomial(n+12,12) mod 12.
%t Table[Mod[Binomial[n+12,n],12],{n,0,110}] (* _Harvey P. Dale_, Oct 13 2017 *)
%Y Cf. A000040, A133620-A133625, A133630, A038509, A133634-A133636, A133910.
%Y See A133872, A133873, A133875, A133877, A133884, A133886, A133888, A133889, A133890 for sequences with different values of p.
%Y See A133900 for the respective periods regarding other values of p.
%K nonn
%O 0,3
%A _Hieronymus Fischer_, Oct 16 2007