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%I #7 Nov 09 2013 03:40:00
%S 1834,4023,8909,15643,27467,50525,78119,123859,185921,253261,332695,
%T 451781,606507,764567,985823,1239911,1480051,1767711,2112517,2516723,
%U 3071485,3712769,4312457,4965713,5555773,6085997,7104079,8259443
%N Sum of third powers of five consecutive primes.
%F a(n) = A133525(n) + A030078(n+4). - _Michel Marcus_, Nov 09 2013
%e a(1)=1834 because 2^3+3^3+5^3+7^3+11^3=1834.
%t a = 3; Table[Prime[n]^a + Prime[n + 1]^a + Prime[n + 2]^a + Prime[n + 3]^a + Prime[n + 4]^a, {n, 1, 100}]
%t Total[#^3]&/@Partition[Prime[Range[40]],5,1] (* _Harvey P. Dale_, May 01 2013 *)
%Y Cf. A034963, A133524, A133525, A133526, A133527, A133528, A133529, A133530, A133531, A133532, A069484, A133534, A133535, A133536, A133537, A034964, A133538, A133540, A133541, A133542, A133543.
%K nonn
%O 1,1
%A _Artur Jasinski_, Sep 14 2007