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%I #5 Nov 09 2013 03:38:58
%S 722,3107,17667,45603,126723,242403,493683,1117443,1910643,3504963,
%T 5623443,8118723,11124243,16188963,24887523,33853683,46114323,
%U 59408643,73961043,92760003,114806643,149150643,198729843,255331923,305140563
%N Sum of fourth powers of three consecutive primes.
%F a(n) = A133535(n) + A030514(n+2). - _Michel Marcus_, Nov 09 2013
%e a(1)=722 because 2^4+3^4+5^4=722.
%t a = 4; Table[Prime[n]^a + Prime[n + 1]^a + Prime[n + 2]^a, {n, 1, 100}]
%Y Cf. A034963, A133524, A133525, A133526, A133527, A133528, A133529, A133530, A133532, A133533.
%K nonn
%O 1,1
%A _Artur Jasinski_, Sep 14 2007