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%I #6 Mar 30 2012 17:27:54
%S 1,2,3,4,8,5,6,9,7,10,14,15,27,13,17,11,19,16,12,22,23,29,33,20,35,42,
%T 28,34,40,24,18,31,32,26,70,41,21,30,51,46,38,39,55,56,57,50,60,43,25,
%U 87,97,64,47,83,85,48,49,69,71,52,93,84,54,76,77,45,79,58,144,81,61,72
%N Inverse permutation to sequence A132988.
%H Klaus Brockhaus, <a href="/A132989/b132989.txt">Table of n, a(n) for n = 1..10000</a>
%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>
%e A132988(11) = 16, hence a(16) = 11; A132988(15) = 12, hence a(12) = 15.
%o (PARI) {m=150; v=vector(m); w=vectorsmall(4*m); for(n=1, m, k=1; while(w[k]||(prime(n)+1)%k>0, k++); v[n]=k; w[k]=1); u=vector(m); for(j=1, m, a=v[j]; if(0<a&&a<=m, u[a]=j)); j=1; while(j<=m&&u[j]>0, print1(u[j], ","); j++)}
%Y Cf. A132988.
%K nonn
%O 1,2
%A _Klaus Brockhaus_, Sep 14 2007