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%I #6 Sep 23 2015 15:40:52
%S 0,1,3,6,11,15,24,49,75,126,251,375,624,1249,1875,3126,6251,9375
%N a(3n+k) = 3a(3n+k-1)-3a(3n+k-2)+2a(3n+k-3) for k = 0,1; a(3n+2) = 3a(3n-1)-3a(3n-2), with a(0) = 0,a(1) = 1,a(2) = 3.
%H <a href="/index/Rec#order_05">Index entries for linear recurrences with constant coefficients</a>, signature (1, -1, 5, -5, 5).
%F Sequence is identical to its third differences in absolute values.
%F G.f.:-x*(x+1)*(3*x^2+x+1)/((x^2-x+1)*(5*x^3-1)) [From Maksym Voznyy (voznyy(AT)mail.ru), Aug 12 2009]
%t LinearRecurrence[{1, -1, 5, -5, 5},{0, 1, 3, 6, 11},18] (* _Ray Chandler_, Sep 23 2015 *)
%K nonn
%O 0,3
%A _Paul Curtz_, Nov 02 2007
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