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a(n) = (Product_{i=1..9} n^i+i) / 9!.
2

%I #15 Jan 03 2016 10:40:54

%S 1,10,524816325,15995379784360900,5136081211768056707885,

%T 104827108835105429096703456,359044402823940369662885183425,

%U 354548318931625565271233374406000,140230322081790179721500725877795625,27516367648544953143193233240569070880,3102623679344954347223585172112606310061

%N a(n) = (Product_{i=1..9} n^i+i) / 9!.

%C See A131685 about well-definedness. - _M. F. Hasler_, May 02 2015

%t Table[Product[ n^i + i, {i, 1, 9}]/9!, {n, 0, 10}] (* _Michael De Vlieger_, Jan 03 2016 *)

%o (PARI) A131679(n,k=9)=prod(i=1,k,(n^i+i))/k! \\ Changing the optional 2nd argument allows one to produce A000027 (k=1), A064808 (k=2), A131509 (k=3), A129995 (k=4), A131675 (k=5), ..., A131680 (k=10). - _M. F. Hasler_, May 02 2015

%K nonn,easy

%O 0,2

%A _Alexander R. Povolotsky_, Sep 15 2007

%E Definition made explicit by _M. F. Hasler_, May 02 2015