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A130631
Multiplicative persistence of Fibonacci numbers.
0
0, 0, 0, 0, 0, 0, 0, 1, 1, 2, 3, 3, 2, 2, 4, 1, 2, 3, 2, 2, 2, 1, 4, 2, 3, 1, 3, 3, 4, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 3, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 2, 1, 1, 1, 1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1
OFFSET
0,10
COMMENTS
From the 184th terms on all the Fibonacci numbers have some digits equal to zero (see A076564), thus their persistence is equal to 1.
FORMULA
a(n) = A031346(A000045(n)). - Michel Marcus, Feb 11 2025
EXAMPLE
3524578 -> 3*5*2*4*5*7*8 = 33600 -> 3*3*6*0*0 = 0 -> persistence = 2.
MAPLE
P:=proc(n)local f0, f1, f2, i, k, w, ok, cont; f0:=0; f1:=1; print(0); print(0); for i from 0 by 1 to n do f2:=f1+f0; f0:=f1; f1:=f2; w:=1; ok:=1; k:=f2; if k<10 then print(0); else cont:=1; while ok=1 do while k>0 do w:=w*(k-(trunc(k/10)*10)); k:=trunc(k/10); od; if w<10 then ok:=0; print(cont); else cont:=cont+1; k:=w; w:=1; fi; od; fi; od; end: P(100);
MATHEMATICA
Table[Length[NestWhileList[Times@@IntegerDigits[#]&, Fibonacci[n], #>=10&]], {n, 0, 102}]-1 (* James C. McMahon, Feb 11 2025 *)
CROSSREFS
Sequence in context: A107901 A334236 A030423 * A282014 A390432 A241539
KEYWORD
easy,nonn,base
AUTHOR
STATUS
approved