OFFSET
1,1
COMMENTS
Can three squares with consecutive prime sides prime(i), i=k,...,k+2, be contained/morphed in a larger square also with prime sides just slightly greater than required?
The areas are the squares of the prime sides; the total area is their sum prime(k)^2 + prime(k+1)^2 + prime(k+2)^2, and pulling the square root is the diagonal of the hosting square. The sequence lists the first, prime(k), if this diagonal (rounded up) is a prime number, indicating that a rather tight enclosing square with (again) a prime side length can be found.
FORMULA
EXAMPLE
Take 13,17,19 with summed squares 169 + 289 + 361 = 819 = A133529(6). The square root is approximately 28.6 and rounding up to 29 yields a prime, so 13 is a term.
MATHEMATICA
Select[Partition[Prime[Range[400]], 3, 1], PrimeQ[Ceiling[ Sqrt[ Total[ #^2]]]]&][[All, 1]] (* Harvey P. Dale, Feb 05 2019 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
J. M. Bergot, May 30 2007
EXTENSIONS
Edited and extended by R. J. Mathar, Jul 10 2011
STATUS
approved