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%I #4 Feb 18 2022 22:27:11
%S 1,0,1,1,0,1,0,0,0,1,3,0,0,0,1,0,1,0,0,0,1,5,0,0,0,0,0,1,0,0,0,0,0,0,
%T 0,1,0,0,1,0,0,0,0,0,1,0,3,0,0,0,0,0,0,0,1
%N A054525 * A129691(unsigned).
%C Row sums = A070777: (1, 1, 2, 1, 4, 2, 6, 1, 2, 4, ...). A129691 = the unsigned inverse of A054523.
%F Moebius transform of A129691
%e First few rows of the triangle:
%e 1;
%e 0, 1;
%e 1, 0, 1;
%e 0, 0, 0, 1;
%e 3, 0, 0, 0, 1;
%e 0, 1, 0, 0, 0, 1;
%e 5, 0, 0, 0, 0, 0, 1;
%e 0, 0, 0, 0, 0, 0, 0, 1;
%e 0, 0, 1, 0, 0, 0, 0, 0, 1;
%e ...
%Y Cf. A054525, A129691, A070777, A054523.
%K nonn,tabl
%O 1,11
%A _Gary W. Adamson_, Apr 29 2007
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