A127859 - OEIS

%I #12 Jul 29 2023 05:00:38

%S 7,79,943,11311,135727,1628719,19544623,234535471,2814425647,

%T 33773107759,405277293103,4863327517231,58359930206767,

%U 700319162481199,8403829949774383,100845959397292591,1210151512767511087

%N a(n) = r(A127858(n)), where r if the cyclic replacement map of the digits d of n in base 12 defined by d->d+1 if d<11 and d->0 if d=11.

%C In base 12 the sequence is 7, 67, 667, 6667, 66667, 666667, 6666667, 66666667, 666666667, 6666666667.

%F a(n) = 6*(12^n - 1)/11 + 1. - _Max Alekseyev_, Jul 27 2023

%e a(2)=66 since, in base 12, 66=56, r(56)=67 and r(56^2)=r(2630)=3741=67^2.

%e In base 12, a(2)=r(A127858(2))=r(56)=67. In base 10, 67 is 79.

%Y Cf. A117755, A127856, A127857, A127858, A127860, A127861, A192544.

%K nonn,base

%O 1,1

%A _Walter Kehowski_, Feb 04 2007

%E More terms from _Max Alekseyev_, Jul 27 2023