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Inverse of number triangle mod(C(floor(k/2),n-k),2).
1

%I #2 Mar 30 2012 18:59:19

%S 1,0,1,0,0,1,0,0,-1,1,0,0,1,-1,1,0,0,0,0,0,1,0,0,-1,1,-1,0,1,0,0,1,-1,

%T 1,-1,-1,1,0,0,0,0,0,1,0,-1,1,0,0,0,0,0,1,0,-1,0,1,0,0,-1,1,-1,1,1,-1,

%U 0,0,1

%N Inverse of number triangle mod(C(floor(k/2),n-k),2).

%C Row sums are A085357. Inverse of A127829.

%e Triangle begins

%e 1,

%e 0, 1,

%e 0, 0, 1,

%e 0, 0, -1, 1,

%e 0, 0, 1, -1, 1,

%e 0, 0, 0, 0, 0, 1,

%e 0, 0, -1, 1, -1, 0, 1,

%e 0, 0, 1, -1, 1, -1, -1, 1,

%e 0, 0, 0, 0, 0, 1, 0, -1, 1,

%e 0, 0, 0, 0, 0, 1, 0, -1, 0, 1,

%e 0, 0, -1, 1, -1, 1, 1, -1, 0, 0, 1

%K sign,tabl

%O 0,1

%A _Paul Barry_, Feb 01 2007