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Floor((n*(n+1)^3/8)^n)-(n!)^4.
1

%I #3 Mar 30 2012 16:50:40

%S 0,0,29,12528,14927013,44632974375,289553896419667,

%T 3621335176611561472,79763800168579144103361,

%U 2886490238072828615188093125,162510049064391484117789761805165,13624190843866457706897020192739557376,1640800492737366435568874082163705520197134

%N Floor((n*(n+1)^3/8)^n)-(n!)^4.

%C Theorem: (n*(n+1)^3/8)^n > (n!)^4 for n > 1.

%D D. S. Mitrinovic, Analytic Inequalities, Springer-Verlag, 1970; p. 193, 3.1.17.

%e (n*(n+1)^3/8)^n - (n!)^4 gives 0, 0, 473/16, 12528, 238832209/16, 44632974375, 1186012759734957321/4096, ...

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Apr 02 2007