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Maximal value of m such that 31^m <= n! : a(n) = floor( log(n!) / log(31) ).
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%I #7 Sep 04 2015 10:27:30

%S 0,0,0,0,1,1,2,3,3,4,5,5,6,7,8,8,9,10,11,12,13,14,15,15,16,17,18,19,

%T 20,21,22,23,24,25,26,27,28,29,31,32,33,34,35,36,37,38,39,40,42,43,44,

%U 45,46,47,49,50,51,52,53,54

%N Maximal value of m such that 31^m <= n! : a(n) = floor( log(n!) / log(31) ).

%o (PARI) a(n) = floor( log(n!) / log(31) ); \\ _Michel Marcus_, Nov 02 2013

%o (PARI) a(n)=lngamma(n+1)\log(31) \\ _Charles R Greathouse IV_, Sep 04 2015

%o (PARI) a(n)=logint(n!,31) \\ _Charles R Greathouse IV_, Sep 04 2015

%Y Cf. A067850, A127031, A127032, A127033, A127034, A127035, A127036, A127037, A127039.

%K nonn

%O 1,7

%A _Artur Jasinski_, Jan 03 2007