%I #8 May 09 2016 14:32:20
%S 0,0,0,0,1,1,2,3,3,4,5,5,6,7,8,9,9,10,11,12,13,14,15,16,17,18,19,20,
%T 21,22,23,24,25,26,27,28,29,30,31,32,33,34,36,37,38,39,40,41,42,44,45,
%U 46,47,48,49,51,52,53,54,56
%N Maximal value of m such that 29^m <= n! : a(n) = floor( log(n!) / log(29) ).
%t Table[Floor[Log[29,n!]],{n,60}] (* _Harvey P. Dale_, May 09 2016 *)
%o (PARI) a(n)=lngamma(n+1)\log(29) \\ _Charles R Greathouse IV_, Sep 02 2015
%o (PARI) a(n)=logint(n!,29) \\ _Charles R Greathouse IV_, Sep 04 2015
%Y Cf. A067850, A127031, A127032, A127033, A127034, A127035, A127036, A127037, A127039.
%K nonn
%O 1,7
%A _Artur Jasinski_, Jan 03 2007
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