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Maximal value of m such that 5^m <= n! : a(n) = floor( log(n!) / log(5) ).
11

%I #4 Nov 16 2021 14:23:04

%S 0,0,1,1,2,4,5,6,7,9,10,12,14,15,17,19,20,22,24,26,28,30,32,34,36,38,

%T 40,42,44,46,48,50,52,55,57,59,61,63,66,68,70,73,75,77,80,82,85,87,89,

%U 92,94,97,99,102,104,107,109,112,114,117

%N Maximal value of m such that 5^m <= n! : a(n) = floor( log(n!) / log(5) ).

%t With[{c=Log[5]},Table[Floor[Log[n!]/c],{n,60}]] (* _Harvey P. Dale_, Nov 16 2021 *)

%Y Cf. A067850, A127031, A127032, A127033, A127034, A127035, A127036, A127037, A127039.

%K nonn

%O 1,5

%A _Artur Jasinski_, Jan 03 2007