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Divide the circle into ten "decants" (each of 36 degrees). Let z = 1/2 + i*14.134725142... be the first nontrivial zero of the Riemann zeta function. Then a(n) is the decant containing the argument of 1/n^z.
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%I #8 Aug 10 2019 00:51:47

%S 1,5,-5,-2,4,-1,-4,4,1,-2,-4,5,3,1,-1,-3,-4,5,4,3,2,1,-1,-2,-3,-4,-5,

%T -5,5,4,3,3,2,1,1,-1,-2,-2,-3,-3,-4,-5,-5,5,5,4,4,3,3,2

%N Divide the circle into ten "decants" (each of 36 degrees). Let z = 1/2 + i*14.134725142... be the first nontrivial zero of the Riemann zeta function. Then a(n) is the decant containing the argument of 1/n^z.

%F Given the first Riemann nontrivial zero, z = (1/2 + i*14.134725142...), extract the argument of 1/n^z (in polar coordinates) and map it on a unit circle by decants: (0 to 36 deg. = 1), (36 to 72 deg. = 2), (72 to 108 deg. = 3), (108 to 144 deg. = 4), (144 to 180 deg. = 5), (0 to -36 deg. = -1), (-36 to -72 deg. = -2), (-72 to -108 deg. = -3), (-108 to -144 deg. = -4), (-144 to -180 deg. = -5).

%e a(5) = 4 since 1/4^z = has angle 136.58045... and the argument is between 108 and 144 deg., which is the 4th decant.

%Y Cf. A100060.

%K more,sign

%O 1,2

%A _Gary W. Adamson_, Nov 28 2006

%E Edited by _N. J. A. Sloane_, Aug 10 2019