login
a(n) = least integer k>=0 such that n=Floor[(3^j)/(5^k)] for some integer j>=0.
1

%I #2 Mar 30 2012 18:57:06

%S 0,5,0,8,1,5,9,13,0,4,6,8,10,12,14,1,3,5,20,7,37,9,11,26,13,28,0,30,2,

%T 32,4,19,34,6,36,8,23,38,10,25,40,12,55,27,42,14,29,1,16,59,31,3,18,

%U 61,33,5,48,20,35,78,7,22,65,37,80,9,24,67,39,82,11,97,26,112,41,84,13,99

%N a(n) = least integer k>=0 such that n=Floor[(3^j)/(5^k)] for some integer j>=0.

%C Every nonnegative integers occurs infinitely many times. The j-sequence is A124906.

%e 1=[3^0/5^0], 2=[3^8/5^5], 3=[3^1/5^0], 4=[3^13/5^8],...,

%e so j-sequence=(0,8,1,13,...); k-sequence=(0,5,0,8,...).

%Y Cf. A124906.

%K nonn

%O 1,2

%A _Clark Kimberling_, Nov 12 2006