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a(n) = H(n)*n!/(floor(n/2))!, where H(n) = sum{k=1 to n} 1/k, the n-th harmonic number.
3

%I #7 Apr 09 2014 10:16:40

%S 0,1,3,11,25,137,294,2178,4566,42774,88572,1004532,2064504,27503832,

%T 56243184,860945040,1754322480,30342400560,61664980320,1189277851680,

%U 2412077832000,51324077044800,103928089910400,2418504655996800

%N a(n) = H(n)*n!/(floor(n/2))!, where H(n) = sum{k=1 to n} 1/k, the n-th harmonic number.

%t f[n_] := HarmonicNumber[n]n!/Floor[n/2]!; Table[f@n, {n, 0, 23}] - _Robert G. Wilson v_, Nov 26 2006

%Y Cf. A123989, A124079.

%K easy,nonn

%O 0,3

%A _Leroy Quet_, Nov 24 2006

%E More terms from _Robert G. Wilson v_, Nov 26 2006