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Recurrence sequence derived from the digits of the square root of 3 after its decimal point.
3

%I #11 Jul 12 2015 16:22:04

%S 0,4,22,215,2737,8636,20805,38867,1868,6505,5767,1004,1216,11702,

%T 55995,43202,314308,2100749,2420235,7750204,5141127,2950527,3113789,

%U 42198,119161,96031,77643,10695,105061,37099,176209,3390478,4549989,9038843

%N Recurrence sequence derived from the digits of the square root of 3 after its decimal point.

%F a(0) = 0; for i >= 0, a(i+1) = position of first occurrence of a(i) in decimal places of sqrt(3).

%e sqrt(3) = 1.73205080756887729352744634151...

%e So for example, with a(0) = 0, a(1) = 4 because the 4th digit after the decimal point is 0; a(2) = 22 because the 22nd digit after the decimal point is 4 and so on.

%p with(StringTools): Digits:=10000: G:=convert(evalf(sqrt(3)),string): a[0]:=0: for n from 1 to 6 do a[n]:=Search(convert(a[n-1],string), G)-2:printf("%d, ",a[n-1]):od: # _Nathaniel Johnston_, Apr 30 2011

%Y Other recurrence sequences: A097614 for Pi, A098266 for e, A098289 for log(2), A098290 for Zeta(3), A098319 for 1/Pi, A098320 for 1/e, A098321 for gamma, A098322 for G, A098323 for 1/G, A098324 for Golden Ratio (phi), A098325 for sqrt(Pi), A098326 for sqrt(2), A189893 for sqrt(5), A098327 for sqrt(e), A098328 for 2^(1/3).

%K base,nonn

%O 0,2

%A _Ryan Propper_, Jul 21 2006