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A120401
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Construct the sequence given by the floor of the imaginary part of zeros of the Riemann zeta function; take complement.
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4
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0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15, 16, 17, 18, 19, 20, 22, 23, 24, 26, 27, 28, 29, 31, 33, 34, 35, 36, 38, 39, 41, 42, 44, 45, 46, 47, 50, 51, 53, 54, 55, 57, 58, 61, 62, 63, 64, 66, 68
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OFFSET
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0,3
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COMMENTS
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LINKS
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EXAMPLE
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The first zero is 14.13472.. so 0,1,2,3,4,5,6,7,8,9,10,11,12,13 are part of the sequence.
The second zero is 21.02203.. so 15,16,17,18,19,20 are in the sequence too.
The third zero is 25.0108.. so we get 22,23,24, etc.
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CROSSREFS
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KEYWORD
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fini,nonn
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AUTHOR
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STATUS
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approved
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