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a(1)=6; a(n)=floor((53+sum(a(1) to a(n-1)))/8).
1

%I #6 Jan 05 2016 18:29:14

%S 6,7,8,9,10,11,13,14,16,18,20,23,26,29,32,36,41,46,52,58,66,74,83,93,

%T 105,118,133,150,168,189,213,240,270,303,341,384,432,486,547,615,692,

%U 778,876,985,1108,1247,1403,1578,1775,1997,2247,2528,2844,3199,3599

%N a(1)=6; a(n)=floor((53+sum(a(1) to a(n-1)))/8).

%H Harvey P. Dale, <a href="/A120199/b120199.txt">Table of n, a(n) for n = 1..1000</a>

%t nxt[{t_,a_}]:=Module[{c=Floor[(53+t)/8]},{t+c,c}]; Transpose[ NestList[ nxt,{6,6},60]][[2]] (* _Harvey P. Dale_, Jan 05 2016 *)

%Y Cf. A073941, A112088, A072493.

%K nonn

%O 1,1

%A _Graeme McRae_, Jun 10 2006

%E More terms from _Harvey P. Dale_, Jan 05 2016