|
%I #8 Oct 03 2013 01:30:25
%S 2,8,98,3624,632148,1008753052,1981162639374
%N a(n) is the smallest number that starts a consecutive block of n numbers with at least n prime divisors (counting multiplicity) each.
%C a(6) is greater than 50000000. - _Tanya Khovanova_ & Alexey Radul, Jul 30 2006
%C a(8) > 10^13. - _Donovan Johnson_, Jan 31 2009
%e Consider a(3): 98 = 2*7*7 (3 prime divisors), 99 = 3*3*11 (3 prime divisors), 100 = 2*2*5*5 (4 prime divisors). Hence 98 starts a consecutive block of 3 numbers with at least 3 prime divisors each. 98 is the smallest such number.
%K hard,more,nonn
%O 1,1
%A _Tanya Khovanova_ & Alexey Radul, Jul 28 2006
%E a(6) from _Donovan Johnson_, Apr 07 2008
%E a(7) from _Donovan Johnson_, Jan 31 2009
| 