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Partial sums of A118605.
0

%I #3 Mar 30 2012 18:50:54

%S 0,1,1,1,2,2,2,2,3,4,4,4,5,5,5,5,5,6,7,7,7,7,7,7,8,9,9,9,9,9,9,9,10,

%T 11,11,12,13,13,13,13,13,13,13,13,14,14,14,14,15,15,16,16,16,16,17,17,

%U 17,17,17,17,17,17,17,17,18,19,19,20,21,22,23,23,24,24,24,24,24,24,24,24

%N Partial sums of A118605.

%C a(n) = number of ones in A118605 in the first n+1 terms.

%K nonn

%O 0,5

%A _Reinhard Zumkeller_, May 09 2006