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%I #3 Mar 30 2012 18:50:54
%S 4,8,9,12,17,18,24,25,32,33,35,36,44,48,50,54,64,65,67,68,69,70,72,80,
%T 81,88,94,96,100,104,108,111,116,122,128,129,130,131,132,134,136,137,
%U 138,140,144,145,160,162,163,174,176,186,189,192,193,200,208,209,215
%N Numbers m such that A118605(m) = 1.
%C A119023(a(n)) <= a(n); complement of A119024.
%K nonn
%O 1,1
%A _Reinhard Zumkeller_, May 09 2006
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