Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).
%I #24 May 06 2023 11:13:23
%S 2,4,7,11,19,33,57,97,166,285,489,838,1436,2462,4221,7236,12404,21264,
%T 36453,62491,107127,183646,314822,539695,925191,1586041,2718927,
%U 4661017,7990313,13697676,23481725,40254377,69007488,118298524,202797424
%N a(n) is the number of binary strings of length n such that no subsequence of length 4 contains 3 or more ones.
%C Also, 3 ones in a row are not allowed - this additional condition is only relevant for a(3) which has no subsequences of length 4.
%C For n>=4, a(n) = the sum of all terms in the n-4th power of the 11 X 11 matrix:
%C [1 1 0 0 0 0 0 0 0 0 0]
%C [0 0 1 1 0 0 0 0 0 0 0]
%C [0 0 0 0 1 1 0 0 0 0 0]
%C [0 0 0 0 0 0 1 0 0 0 0]
%C [0 0 0 0 0 0 0 1 1 0 0]
%C [0 0 0 0 0 0 0 0 0 1 0]
%C [0 0 0 0 0 0 0 0 0 0 1]
%C [1 1 0 0 0 0 0 0 0 0 0]
%C [0 0 1 1 0 0 0 0 0 0 0]
%C [0 0 0 0 1 1 0 0 0 0 0]
%C [0 0 0 0 0 0 0 1 1 0 0]
%C because this matrix represents the transitions from the state where the last four bits are 0000, 0001, 0010, 0011, 0100, 0101, 0110, 1000, 1001, 1010, 1100 to the state after the next bit, always avoiding three 1's out of the last four bits. - _Joshua Zucker_, Aug 04 2006
%C Motivated by radar research. In the standard model to get a track on a target you have to get at least M detections out of N observations. See page 96 of Minkler and Minkler. I represented detections as ones and non-detections as zeros. Hence this sequence represents non-tracked situations with n observations.
%D G. Minkler and J. Minkler, CFAR: The Principles of Automatic Radar Detection in Clutter, Magellan, Baltimore, 1990.
%H Harvey P. Dale, <a href="/A118647/b118647.txt">Table of n, a(n) for n = 1..1000</a>
%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (1,1,0,1,0,-1).
%F a(n) = a(n-1) + a(n-2) + a(n-4) - a(n-6). - suggested by _Jon E. Schoenfield_
%F G.f.: x*(2+2*x+x^2-x^4-x^5) / (1-x-x^2-x^4+x^6). - _Colin Barker_, Oct 01 2014
%t LinearRecurrence[{1,1,0,1,0,-1},{2,4,7,11,19,33},40] (* _Harvey P. Dale_, Oct 03 2016 *)
%o (PARI) Vec(x*(2+2*x+x^2-x^4-x^5)/(1-x-x^2-x^4+x^6) + O(x^100)) \\ _Colin Barker_, Oct 01 2014
%o (Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( x*(2+2*x+x^2-x^4-x^5)/(1-x-x^2-x^4+x^6) )); // _G. C. Greubel_, May 05 2023
%o (SageMath)
%o def A118647_list(prec):
%o P.<x> = PowerSeriesRing(ZZ, prec)
%o return P( x*(2+2*x+x^2-x^4-x^5)/(1-x-x^2-x^4+x^6) ).list()
%o a=A118647_list(41); a[1:] # _G. C. Greubel_, May 05 2023
%Y Complementary to A118646: a(n) = 2^n - A118646(n).
%K nonn,easy
%O 1,1
%A _Tanya Khovanova_, May 10 2006, Aug 17 2006
%E More terms from _Joshua Zucker_, Aug 04 2006